-3s^2-6s+5=0

Solution for -3s^2-6s+5=0 equation:

-3s^2-6s+5=0

a = -3; b = -6; c = +5;
Δ = b2-4ac
Δ = -62-4·(-3)·5
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-4\sqrt{6}}{2*-3}=\frac{6-4\sqrt{6}}{-6}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+4\sqrt{6}}{2*-3}=\frac{6+4\sqrt{6}}{-6}
$